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Apr 22, 2010 at 6:50 comment added Sergei Ivanov @MG: yes. And indeed, too many misprints there. I'll try to find the latest errata (it used to be on YuB's site but somehow disappeared).
Apr 21, 2010 at 21:57 comment added J. GE I see, so $X^5= \{(z_1, z_2, z_3| |z_1|^2+|z_2|^2\le 1, z_1, z_2, z_3\in \mathbb C\}/ \{S^1 action\}$, right?
Apr 21, 2010 at 21:48 vote accept J. GE
Apr 21, 2010 at 20:29 history answered Sergei Ivanov CC BY-SA 2.5