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Oct 16, 2015 at 15:38 comment added Yonatan Harpaz Sorry, then the fibers are not contractible.
Oct 16, 2015 at 15:24 comment added Yonatan Harpaz Right. So take instead the map $B(\mathbb{Z}/2) \to \Delta^0$.
Oct 15, 2015 at 21:54 history edited Tom Goodwillie CC BY-SA 3.0
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Oct 15, 2015 at 21:16 comment added Omar Antolín-Camarena The map $\Delta^0 \to B(\mathbb{Z}/2)$ is not surjective, which is one of the requirements in the question, @YonatanHarpaz.
Oct 15, 2015 at 20:13 comment added Yonatan Harpaz Let $X$ be the nerve of the groupoid with one object and two automorphisms (also known as the classifying space of $\mathbb{Z}/2$). Then $X$ is a Kan complex with just one vertex but the corresponding map $\Delta^0 \to X$ does not induce an isomorphism on $H^1$ with coefficients in $\mathbb{Z}/2$
Oct 15, 2015 at 18:32 comment added Ilias A. in my version, X and Y are Kan complexes. Can you provide a counterexample?
Oct 15, 2015 at 18:24 history answered Tom Goodwillie CC BY-SA 3.0