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Oct 16, 2015 at 15:00 vote accept Acapello
Oct 15, 2015 at 16:46 comment added Carlo Beenakker yep, it's that simple
Oct 15, 2015 at 16:44 comment added David E Speyer @CarloBeenakker $S_n^n=1$, yes?
Oct 15, 2015 at 16:43 answer added David E Speyer timeline score: 6
Oct 15, 2015 at 16:42 comment added Carlo Beenakker this is just $n! S_n^n$, the Stirling number of the second kind.
Oct 15, 2015 at 16:38 review First posts
Oct 15, 2015 at 16:46
Oct 15, 2015 at 16:38 history asked Acapello CC BY-SA 3.0