Skip to main content
9 events
when toggle format what by license comment
Oct 25, 2015 at 6:48 comment added cardinal Do you have the first inequality sign in the display equation backwards?
Oct 14, 2015 at 20:28 comment added gappy3000 Carlo, it makes sense but can you think of a counterexample?
Oct 13, 2015 at 20:00 comment added Carlo Beenakker how can you exclude with exponentially small probability that $Y_i\approx -X_i$? I would expect a power law in $\epsilon^2$, not an exponential.
Oct 13, 2015 at 19:43 comment added Kevin P. Costello I guess $c$ here is allowed to depend on the distribution of the $X_i$ somehow? (If not, what's preventing the $X_i$ from, say, each being $0$ with probability $1-\frac{1}{N^2}$).
Oct 13, 2015 at 15:42 comment added gappy3000 Yes, I agree. I believe the RHS could be an even stronger $\exp(-cN\epsilon^2)$, but would be happy with the original conjecture.
Oct 13, 2015 at 15:20 comment added Fedor Petrov in any case, $N$ must appear somehow in the inequality
Oct 13, 2015 at 15:18 history edited gappy3000 CC BY-SA 3.0
added 4 characters in body
Oct 13, 2015 at 15:16 comment added Fedor Petrov maybe, another sign of the main inequality?
Oct 13, 2015 at 15:13 history asked gappy3000 CC BY-SA 3.0