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Oct 13, 2015 at 11:10 history edited Alexey Ustinov CC BY-SA 3.0
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Oct 13, 2015 at 9:25 comment added Fedor Petrov It looks like my answer above modified by using functional equation $\psi(x+1)=\psi(x)+1/x$.
Oct 13, 2015 at 8:51 comment added Fedor Petrov That is, $f_{n}(x)=\frac{(x+2)^{n+1}-1}{x+1}$, i.e. roots are $w-2$, where $w^{n+1}=1$.
Oct 13, 2015 at 7:50 history answered Alexey Ustinov CC BY-SA 3.0