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Oct 15, 2015 at 14:10 vote accept smyrlis
Oct 14, 2015 at 19:45 comment added Włodzimierz Holsztyński Cont. (finish): The z=0 level curve cannot be contracted because an infinite sequence of the level z=0 points would have to reach the top level z=1 at about the same time during the homotopy. This reaching z=1 would be forced by elementary considerations or by a simple homological argument.
Oct 14, 2015 at 19:39 comment added Włodzimierz Holsztyński Every simple curve is contained in one of the cones. (The example is fine and elegant, of course).
S Oct 14, 2015 at 15:16 history suggested smyrlis CC BY-SA 3.0
LaTeXified the answer
Oct 14, 2015 at 15:08 comment added smyrlis Your space contains the segment $\{(0,0,t) : t\in[0,1]\}$,which appears to cause some trouble. Why do you need the space to be compact? Could you provide some further explanation or a link?
Oct 14, 2015 at 15:05 review Suggested edits
S Oct 14, 2015 at 15:16
Oct 12, 2015 at 20:54 history edited Paul Fabel CC BY-SA 3.0
A partial positive answer is replaced by a counterexample
Oct 12, 2015 at 20:06 history edited Paul Fabel CC BY-SA 3.0
The original post answered a weaker question.
Oct 12, 2015 at 20:00 history answered Paul Fabel CC BY-SA 3.0