Timeline for Counting number of conformations on a non-intersecting lattice walk
Current License: CC BY-SA 2.5
9 events
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Apr 22, 2010 at 4:17 | comment | added | Hooked | Perhaps more simply, two nodes are nearest neighbors on a unit lattice if the Cartesian distance between them is one (with the provision that node $n_i$ is not a nearest neighbor to nodes $n_{i-1}$ or $n_{i+1}$. So no, I don't think this makes it a graph in the usual sense. | |
Apr 22, 2010 at 2:48 | comment | added | Leandro | hi Hooked, I think I am not understanding what you are calling nearest neighbors of a random walk. Suppose that we have a non-intersect walk $\omega=\{v_0,\{v_0,v_1\},v_1,\{v_1,v_2\},\ldots,\{v_{n-1},v_n\},v_n\}$. We can think about it as a graph, I will call it $G$. My question is: what are you calling nearest neighbors pairs of $\omega$ ? Are they the set of pairs $\{v_i,v_j\}\notin E(G)$, satisfying $\|v_i-v_j\|_1=1$ ? ($E(G)$, as usual, is the edge set of $G$ and $\|(z_1,\ldots,z_d)\|_1=\sum_{j=1}^d|z_j|$ | |
Apr 22, 2010 at 0:31 | history | edited | Hooked | CC BY-SA 2.5 |
Correction on example
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Apr 21, 2010 at 23:45 | answer | added | Douglas S. Stones | timeline score: 1 | |
Apr 21, 2010 at 20:43 | history | edited | Hooked | CC BY-SA 2.5 |
added example
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Apr 21, 2010 at 20:01 | comment | added | Yemon Choi | For instance, can you give me a concrete example (with d=2, say) where two paths are supposed to have EXACTLY the same set of nearest neighbours? | |
Apr 21, 2010 at 19:22 | comment | added | Yemon Choi | What does it mean for two non-intersecting walks to have "the same set of nearest neighbors"? | |
Apr 21, 2010 at 15:35 | history | edited | Hooked | CC BY-SA 2.5 |
small grammer fix - added origin to description
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Apr 21, 2010 at 15:23 | history | asked | Hooked | CC BY-SA 2.5 |