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Timeline for A strange polynomial equality

Current License: CC BY-SA 3.0

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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Oct 11, 2015 at 19:01 comment added Dan Romik Well, the Legendre polynomials have the explicit expansion $P_n(x)=2^n \sum_{k=0}^n \binom{n}{k} \binom{(n+k-1)/2}{n} x^k$, so by equating coefficients of $x^m$ on both sides of your strange identity, you will reduce the whole thing to a hypergeometric summation identity. Those can be attacked by standard technology, canonically described in the wonderful book A=B by Petkovsek, Wilf and Zeilberger. I leave the details as an exercise. :-)
Oct 11, 2015 at 10:18 history edited Ilya Bogdanov CC BY-SA 3.0
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Oct 11, 2015 at 9:50 history asked Ilya Bogdanov CC BY-SA 3.0