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Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Oct 31, 2015 at 15:32 vote accept yada
Oct 11, 2015 at 15:22 comment added Nate Eldredge The question of whether $M(\mathbb{R})$ is sequential is addressed by this question, where I showed that $M([0,1])$ is not sequential. Also see this one. Since $M([0,1])$ is a closed subspace of $M(\mathbb{R})$, the latter is not sequential either.
Oct 11, 2015 at 7:39 answer added dalry timeline score: 3
Oct 9, 2015 at 19:45 answer added Alexander Shamov timeline score: 2
Oct 9, 2015 at 16:40 history asked yada CC BY-SA 3.0