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What is the algebraic fundamental groups of $SO(n)$ and $Sp(2n)$?

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Gest2015
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Let $k$ be an algebraiclyalgebraically closed field of characteristic zero. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Let $k$ be an algebraicly closed field of characteristic zero. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Let $k$ be an algebraically closed field of characteristic zero. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Let $k$ be an arbitrary algebraicly closed field of characteristic zero. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Let $k$ be an arbitrary algebraicly closed field. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Let $k$ be an algebraicly closed field of characteristic zero. and let $$\sigma: SL_n(k)\rightarrow SL_n(k)$$
be an involution. My questions are:

  • How could one calculate the fundamental group of $SL_n(k)^\sigma$ ? (the invariant subgroup)

  • In particular, what is $\pi_1(SO_n(k))$ and $\pi_1(Sp_{2n}(k))$?

thanks

Source Link
Gest2015
  • 307
  • 1
  • 11
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