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Oct 12, 2015 at 13:46 vote accept John Binder
Oct 11, 2015 at 22:50 history edited Jim Humphreys CC BY-SA 3.0
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Oct 9, 2015 at 23:52 history edited Jim Humphreys CC BY-SA 3.0
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Oct 8, 2015 at 16:03 comment added John Binder thanks for your comment. It seems we're on the same page now, and I'm glad I wasn't mistaken about cuspidals only coming from anisotropic tori.
Oct 8, 2015 at 15:19 comment added Jim Humphreys @John: Having given the set-up some more thought, I've edited my answer so that the tori in question are anisotropic over the finite field. Sorry for the added confusion. It's true that cuspidal irreducible characters can't occur as constituents in ordinary parabolic induction for proper parabolics, but in the D-L construction a generalized character coming from an anisotropic (or minisotropic) torus may well have a mixture of irreducibles as constituents including both cuspidal and non-cuspidal characters.
Oct 8, 2015 at 15:13 history edited Jim Humphreys CC BY-SA 3.0
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Oct 8, 2015 at 14:34 comment added Jim Humphreys @John: Maybe it's best to include a definition of "minisotropic" in your question? And what would it mean for $R_{T,\theta}$ to be "cuspidal"?
Oct 8, 2015 at 14:28 comment added John Binder thanks for your answer. I've edited the first line to reflect your note on terminology. Re your second point, perhaps I'm mistaken in the following line of reasoning: let $S\leq T$ be the maximal split component and let $A$ be the maximal split component in the center. If $S \supsetneq A$, then $C_G(S)$ is a Levi component $M$ of a proper parabolic subgroup $P$ of $G$, and we have $T \leq M$. Then any $R_{T,\theta}$ is a character induced from a character $\rho$ on $M$, and thus not cuspidal. It's possible there's an error in my understanding.
Oct 8, 2015 at 14:15 history answered Jim Humphreys CC BY-SA 3.0