Timeline for Is the complement of an affine variety always a divisor?
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 20, 2011 at 23:15 | answer | added | Oliver Jones | timeline score: 2 | |
| May 2, 2010 at 7:02 | comment | added | Maharana | A side remark: such a divisor must also be connected if dimension of $X$ is $\geq{2}$ ! | |
| Apr 21, 2010 at 16:20 | vote | accept | Daniel Loughran | ||
| Apr 21, 2010 at 16:15 | vote | accept | Daniel Loughran | ||
| Apr 21, 2010 at 16:20 | |||||
| Apr 21, 2010 at 12:41 | answer | added | Angelo | timeline score: 18 | |
| Apr 21, 2010 at 12:24 | comment | added | BCnrd | Affirmative even in the normal case, but this is a good exercise to work on more on your own. Hint: look at local ring at a generic point of the complement (assuming it is non-empty). As an aside, this plays a key role in producing the ample divisor in the proof that abelian varieties are projective! | |
| Apr 21, 2010 at 11:19 | history | asked | Daniel Loughran | CC BY-SA 2.5 |