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Apr 13, 2017 at 12:58 history edited CommunityBot
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Oct 8, 2015 at 14:16 vote accept Asaf Shachar
Oct 7, 2015 at 15:50 history edited Asaf Shachar CC BY-SA 3.0
minor typo corrected
Oct 7, 2015 at 15:20 comment added Todd Trimble @JasonStarr It's certainly related. One way of thinking about a cleavage of a fibration is that it is given by a pseudofunctor $F: C^{op} \to Cat$ which takes $f: X \to Y$ to a suitable $f^\ast: F(Y) \to F(X)$. A cleavage of the codomain fibration $cod: C^\mathbf{2} \to C$ would then be given by a choice of pullback $f^\ast: C/Y \to C/X$ for each $f: X \to Y$. So having a choice of fiber product for all cospans would give you such a cleavage, although I was really just referring to a single $f$ in my comment.
Oct 7, 2015 at 14:44 comment added Jason Starr @ToddTrimble: Are you referring to a "clivage"?
Oct 7, 2015 at 13:19 comment added Todd Trimble On the nLab, there is I think a growing consensus to apply the phrase "fiber product" to the limit of the cospan, and to apply the word "pullback" to a functor $f^\ast: E/X \to E/Y$ which sends (in the notation of OP's clarification) $f': Y' \to X$ to $g: Z \to Y$ arising in the fiber product, as in "pulling back along $f$".
Oct 7, 2015 at 12:18 comment added Jason Starr Your definition of "pullback" is the definition of categorical fiber product.
Oct 7, 2015 at 10:40 comment added Asaf Shachar @JasonStarr : I have edited the question to clarify this.
Oct 7, 2015 at 10:38 history edited Asaf Shachar CC BY-SA 3.0
added 490 characters in body
Oct 7, 2015 at 10:35 answer added Simon Henry timeline score: 12
Oct 7, 2015 at 10:27 history edited Asaf Shachar CC BY-SA 3.0
added 490 characters in body
Oct 7, 2015 at 10:21 comment added Jason Starr If, for you, the categorical fiber product is not the same as "pullback", can you please define what you mean by "pullback"?
Oct 7, 2015 at 10:10 history asked Asaf Shachar CC BY-SA 3.0