Timeline for Topological embeddings of non-compact, complete metric spaces
Current License: CC BY-SA 2.5
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 27, 2010 at 2:27 | history | edited | Robin Saunders | CC BY-SA 2.5 |
important mistake in 3.
|
| Apr 24, 2010 at 1:33 | answer | added | Ady | timeline score: 6 | |
| Apr 21, 2010 at 20:25 | comment | added | Robin Saunders | Thanks to everyone who's contributed, you've all been very helpful. I'm embarrassed to admit it didn't occur to me that 2 might not imply 3 - I'm still not used to thinking of infinite chains of inclusion. Thanks again! | |
| Apr 21, 2010 at 20:16 | vote | accept | Robin Saunders | ||
| Apr 21, 2010 at 10:32 | comment | added | Gerald Edgar | A metrizable topological space S is compact if and only if every metric on S that induces this topology is complete. | |
| Apr 21, 2010 at 8:56 | answer | added | Sergei Ivanov | timeline score: 7 | |
| Apr 21, 2010 at 8:01 | answer | added | Benoît Kloeckner | timeline score: 5 | |
| Apr 21, 2010 at 5:38 | comment | added | Qiaochu Yuan | A metrizable space has a metrizable compactification if and only if it's second-countable (equivalently, separable). The direction you care about is clear, since any subspace of a compact metric space is second-countable. | |
| Apr 21, 2010 at 5:07 | history | asked | Robin Saunders | CC BY-SA 2.5 |