Timeline for Extensions of $\Bbb Z_3$ by $PGL(2,q)$ where $q$ is odd
Current License: CC BY-SA 3.0
10 events
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Oct 5, 2015 at 11:04 | comment | added | Behsa | I am sorry I mean about a new character degree in one of them which does not exist in other one. | |
Oct 5, 2015 at 10:59 | comment | added | Derek Holt | What do you mean by "this group"? All of the groups we have been discussing have order $3|{\rm PGL}(2,q)|$ so the character degrees will certainly be different from those of ${\rm PGL}(2,q)$. | |
Oct 5, 2015 at 10:55 | comment | added | Behsa | Is there any difference between the character degrees of ${\rm PGL}(2,q)$ and this group? | |
Oct 5, 2015 at 10:53 | vote | accept | Behsa | ||
Oct 5, 2015 at 10:48 | history | edited | Derek Holt | CC BY-SA 3.0 |
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Oct 5, 2015 at 9:04 | comment | added | Behsa | I am very thankful for the complete and very useful comments. | |
Oct 5, 2015 at 8:59 | history | edited | Derek Holt | CC BY-SA 3.0 |
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Oct 5, 2015 at 8:56 | comment | added | Behsa | I am sorry for this mistake. I consider that the Schur Multiplier is equal to 2. And for the second group in the above discussion we have $G\cong S_3\times {\rm PSL}(2,q)$, is this true? | |
Oct 5, 2015 at 8:40 | comment | added | Geoff Robinson | Note that $q = 9$ is a case where there is already non-split extension of $\mathbb{Z}/3\mathbb{Z}$ by ${\rm PSL}(2,9)$ ( I mean by this a perfect triple cover of ${\rm PSL}(2,9)$). | |
Oct 5, 2015 at 8:26 | history | answered | Derek Holt | CC BY-SA 3.0 |