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when toggle format what by license comment
Oct 5, 2015 at 0:38 answer added tmh timeline score: 4
Oct 3, 2015 at 19:15 vote accept James Propp
Oct 3, 2015 at 5:08 answer added Anthony Quas timeline score: 7
Oct 2, 2015 at 20:43 history edited James Propp CC BY-SA 3.0
fixed mistake
Oct 2, 2015 at 19:42 comment added Anthony Quas Wouldn't a logarithmic average do it? $D(A)=\lim_{N\to\infty}1/(\log N)\sum_{n\le N}\mathbf 1_{n\in A}/n$. If not logarithmic, then certainly iterated logarithmic.
Oct 2, 2015 at 19:31 comment added Anthony Quas Is a bit $\pm 1$? Otherwise it's hard for the sum to be $\le 0$.
Oct 2, 2015 at 17:56 history asked James Propp CC BY-SA 3.0