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Apr 22, 2010 at 1:23 comment added Igor Belegradek For Alexandrov spaces (or more generally for Hausdorff paracompact locally contractible spaces) Alexander-Spanier and singular cohomology coincide, as shown in Chapter 6, Section 9, Theorem 1 of Spanier's "Algebraic topology". However this does not simplify matters; how does one prove $H^n(X-x)=0$ for singular cohomology? This is worrisome.
Apr 21, 2010 at 19:04 comment added Sergei Ivanov I was asked this question by Yuri Burago who was asked by another guy whose name I forgot. I just want to handle him all details I can.
Apr 21, 2010 at 17:21 comment added Anton Petrunin Sergei, It seems you are convinced that it is true, but you really want to have a clean proof --- that probably means that you have an application. Can I ask what is it?
Apr 20, 2010 at 15:58 history answered Sergei Ivanov CC BY-SA 2.5