Skip to main content
25 events
when toggle format what by license comment
Dec 7, 2016 at 18:49 history edited paul Monsky CC BY-SA 3.0
description of new answers added
Nov 5, 2015 at 15:18 vote accept paul Monsky
Nov 5, 2015 at 15:16 history edited paul Monsky CC BY-SA 3.0
Gave an application of my first answer, deleted one of the further questions and added a tag.Corrected a typo.
Nov 1, 2015 at 11:46 answer added paul Monsky timeline score: 1
Oct 30, 2015 at 14:48 answer added paul Monsky timeline score: 3
Oct 27, 2015 at 18:16 history edited paul Monsky CC BY-SA 3.0
A new question related to the recursion is raised.
Oct 11, 2015 at 20:09 history edited paul Monsky CC BY-SA 3.0
Characteristic 3 analogues added, typo corrected.
Oct 11, 2015 at 19:19 history edited paul Monsky CC BY-SA 3.0
added 812 characters in body
Oct 2, 2015 at 3:10 comment added Alexey Ustinov $c(0)+c(1)+c(2)+\ldots=1+x^2+x^4+\ldots=(1+x^2)^{-1}$.
Oct 2, 2015 at 0:40 comment added paul Monsky Then U_3 takes (r+r^2)*(r^2n) into what in your notation is (r+r^2)*(a(n) evaluated at r^2). So your a(n) describe the action of U_3 on the space of (odd) forms, while the c(n) describe the action of the (locally nilpotent) operator I+U_3 on the space. The situation is similar for the second equation.
Oct 2, 2015 at 0:31 comment added paul Monsky Hi Will. Here's how the first equation arises. Let F and G be the mod 2 reductions of delta(z) and delta(3z). There is a mod 2 modular form of level 3, generating the ring of such forms, with r^4+r^3+r^2+r=F, and r^4+r^3=G,
Oct 2, 2015 at 0:20 comment added paul Monsky Hi Joe. I've actually been on MO for 5 years as an unregistered user, but my old computer wasn't working well, so I started a separate account on the new one. Someday I'll get them merged. If you go into the modular forms or characteristic p tags, you can find my old questions and answers.
Oct 1, 2015 at 23:20 comment added Joe Silverman Hi Paul, Welcome to MathOverflow. I edited your question to make it easier to read, hope you don't mind. I also fixed the Z_2 by changing it back to Z/2Z. Interesting question.
Oct 1, 2015 at 23:17 history edited Joe Silverman CC BY-SA 3.0
Fixed the LaTeX to make it easier to read
Oct 1, 2015 at 22:24 answer added Peter Mueller timeline score: 2
Oct 1, 2015 at 21:13 comment added Will Sawin Do the coefficients for writing $c(n)$ as a sum of previous ones possibly stabilize?
Oct 1, 2015 at 21:13 comment added Will Sawin WhaIt seems like $c(n)$ can be written as $a(n)+b(n)$ where $a(n)$ satisfies $c(n+4)=c(n+3)+(x^4+x^3+x^2+x)$ and $b(n) = x^n$. The equation for $a(n)$ is related to the curve $y^4-y^3 = x^4+x^3+x^2+x$. Do you think this perspective is unhelpful?
Oct 1, 2015 at 20:40 history edited paul Monsky CC BY-SA 3.0
related question proposed
Sep 30, 2015 at 7:11 comment added joro @paulMonsky You can edit it yourself to Z/2, select "edit" below the question.
Sep 30, 2015 at 6:37 comment added paul Monsky @KConrad Yes--my Z/2 got edited to Z_2, but the title shows I don't mean the 2-adics.
Sep 30, 2015 at 5:05 comment added KConrad Are you writing $\mathbb Z_2$ for $\mathbb F_2$?
Sep 30, 2015 at 1:44 comment added Per Alexandersson I edited to make it look good in LaTeX, but please check that $c(n)$ in the right set, that is, polynomials with coefficients taken mod 2.
Sep 30, 2015 at 1:43 history edited Per Alexandersson CC BY-SA 3.0
texed
Sep 30, 2015 at 1:34 review First posts
Sep 30, 2015 at 2:05
Sep 30, 2015 at 1:33 history asked paul Monsky CC BY-SA 3.0