Timeline for reductive Lie subalgebra
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 21, 2010 at 7:42 | vote | accept | Michele Torielli | ||
| S Apr 21, 2010 at 7:42 | vote | accept | Michele Torielli | ||
| Apr 21, 2010 at 7:42 | |||||
| Apr 21, 2010 at 7:41 | vote | accept | Michele Torielli | ||
| S Apr 21, 2010 at 7:42 | |||||
| Apr 20, 2010 at 16:09 | answer | added | Robin Chapman | timeline score: 4 | |
| Apr 20, 2010 at 14:46 | vote | accept | Michele Torielli | ||
| Apr 21, 2010 at 7:41 | |||||
| Apr 20, 2010 at 14:40 | answer | added | Ben Webster♦ | timeline score: 2 | |
| Apr 20, 2010 at 14:39 | comment | added | Michele Torielli | The fact is that I have in mind a specific example: L is the set of weight zero vector fields in C^n and G is the set of vector fields tangent to an hypersurface. | |
| Apr 20, 2010 at 14:33 | comment | added | Michele Torielli | It is true.But If L doesn't decompose like that? | |
| Apr 20, 2010 at 14:26 | comment | added | Robin Chapman | The answer to your first question is rather obviously no, since if $L = G \times H$ with H abelian then every element $l\in H$ has $[l,g]=0\in G$. | |
| Apr 20, 2010 at 14:14 | history | asked | Michele Torielli | CC BY-SA 2.5 |