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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Sep 29, 2015 at 16:22 comment added Ali Taghavi @QiaochuYuan Thanks for your comment. However for a particular functor "commutator" the answer to this question is negative, see this post mathoverflow.net/questions/219076/…, but this negative answer contains very interesting idea. So, what about if we consider some other functors?
Sep 28, 2015 at 21:11 comment added Qiaochu Yuan I don't see any reason to expect that such things exist, or any use to which they might be put if they did. The operation sending a polynomial to its Galois group is very sensitive and I don't expect it to have basically any good behavior.
Sep 28, 2015 at 16:50 history edited Arturo Magidin CC BY-SA 3.0
put link to previous question, some rephrasings.
Sep 28, 2015 at 16:43 comment added Ali Taghavi @ArturoMagidin Thank you. I revise the title.
Sep 28, 2015 at 16:41 history edited Ali Taghavi CC BY-SA 3.0
edited title
Sep 28, 2015 at 16:27 comment added Arturo Magidin I think the title is misleading. You are not seeking a "functorial approach to Galois theory". You are asking a question about functors and Galois theory, but you are not trying to approach Galois theory functorially.
Sep 28, 2015 at 16:20 comment added Ali Taghavi @j.c. You are welcome. Thank you for your suggestions. based on your comment, I revised the question.
Sep 28, 2015 at 16:17 history edited Ali Taghavi CC BY-SA 3.0
Some clarification
Sep 28, 2015 at 12:11 comment added Ali Taghavi @DimaSustretov $T$ is $\mathbb{Q}$-linear on vector space $\mathbb{Q}[x]$. Please see the linked question.
Sep 28, 2015 at 12:09 comment added j.c. Thanks, I was confused! It might help to include a little more background from the other question to keep this one self-contained. Also it may help to use the term "endofunctor".
Sep 28, 2015 at 12:07 history edited Ali Taghavi CC BY-SA 3.0
edited title
Sep 28, 2015 at 12:07 comment added Ali Taghavi @j.c. $\mathcal{F}$ is a functor on category of groups, for example, in the linked question I considered $\mathcal{F}= commutator$ and according to the answer to that question I realized that this functor is Galoois related to no linear map $T$.
Sep 28, 2015 at 11:24 history edited Ali Taghavi CC BY-SA 3.0
added 37 characters in body
Sep 28, 2015 at 11:16 history edited Ali Taghavi CC BY-SA 3.0
deleted 1 character in body
Sep 28, 2015 at 11:09 history asked Ali Taghavi CC BY-SA 3.0