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Oct 3, 2015 at 8:10 vote accept Tian An
Sep 26, 2015 at 12:22 comment added მამუკა ჯიბლაძე Oh sorry I just did not notice the word "argument" :D
Sep 26, 2015 at 12:12 comment added juan @ მამუკა ჯიბლაძე @paul garrett No, I mean $\sigma=1$, I speak of the function $\arg \zeta(1+i t)$. This is real analytic vanishes at $c T$ points (think on the x-ray, but this can be proved ). Also we know how to compute the probabilities I speak about.
Sep 26, 2015 at 11:57 comment added მამუკა ჯიბლაძე @juan You mean $\sigma=\frac12$ I believe?
Sep 26, 2015 at 10:30 comment added juan In what sense use you the word regular? "... the argument of zeta of the line $\sigma=1$ becomes very regular". Of course it is a real analytic function. But, for $0<t<T$ there are $cT$ points where it is $=0$. But it is not bounded. The probability to be greater than $2\pi$ being very small, to be $\ge 4\pi$ almost incredibly small, and so on. I will not call this behavior "regular".
Sep 25, 2015 at 23:41 comment added Tian An +1 Thank you for the very nice reference!
Sep 25, 2015 at 23:26 history answered paul garrett CC BY-SA 3.0