Timeline for Minimisers and critical points of variational integrals
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 28, 2015 at 22:48 | history | edited | Nirav | CC BY-SA 3.0 |
corrected spelling
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| Sep 27, 2015 at 22:57 | comment | added | Math604 | any dimension is fine.. | |
| Sep 27, 2015 at 22:07 | history | edited | Nirav | CC BY-SA 3.0 |
made question clearer
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| Sep 27, 2015 at 22:06 | comment | added | Nirav | Sorry, in the question I meant that both the critical point and the minimiser's are non-constant...Also am I correct in assuming that $\Omega\subset\mathbb{R}^2$ in the above example? | |
| Sep 27, 2015 at 20:06 | comment | added | Math604 | Consider $$ I(u)= \frac{1}{2} \int_\Omega | \nabla u|^2 + \frac{1}{4} \int_\Omega u^4 - \frac{\lambda}{2} \int_\Omega u^2$$ where $ \lambda>\lambda_1 $ (first eigenvalue of $ -\Delta $). This should have two non-zero minimizers and $0$ should also be a critical point... | |
| Sep 24, 2015 at 16:13 | history | asked | Nirav | CC BY-SA 3.0 |