Timeline for Is there a $\mathbb{Q}$-linear map $T$ over $\mathbb{Q}[x]$ such that for all polynomials $Gal(T(f))$ $\simeq$ The commutator subgroup of $Gal(f)$?
Current License: CC BY-SA 3.0
1 event
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 24, 2015 at 4:37 | history | answered | Anthony Quas | CC BY-SA 3.0 |