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Sep 22, 2015 at 18:50 answer added Todd Trimble timeline score: 9
Sep 22, 2015 at 18:46 comment added user44591 @Zhen Lin: I think all extremal monomorphisms are closed embeddings in Hausdorff spaces. If $f:X \rightarrow Y$ is an extremal mono ,consider $Z = \overline{f(X)}$ (the closure of the images) and let $g:X \rightarrow Z$ be the obvious map and $i: Z \rightarrow Y$ the inclusion. $g$ is an epi in the category of Hausdorff spaces,since it has dense image, so is an iso since f is supposed to be extremal. In the category of Hausdorff spaces, closed embeddings are regular monomorphisms, and since every regular monomorphism is extremal, the claim should follow.
S Sep 22, 2015 at 18:17 history suggested CommunityBot CC BY-SA 3.0
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S Sep 22, 2015 at 18:17
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Sep 22, 2015 at 17:35 history asked Carlson CC BY-SA 3.0