Skip to main content
7 events
when toggle format what by license comment
Jun 2, 2020 at 18:55 vote accept Alex Ravsky
Feb 9, 2020 at 2:48 answer added YCor timeline score: 2
Feb 9, 2020 at 2:16 history edited YCor CC BY-SA 4.0
removed unnecessary sentences, added tag
Sep 22, 2015 at 7:25 comment added Dave Witte Morris I assume the order is translation invariant. Then I think people usually express this condition by saying that the order is "dense" (meaning that if $a < b$, then there exists $x$, such that $a < x < b$). So the group is "densely ordered". However, an alternative would be to say that the order has no isolated points (if $a < x < b$, then there exists $y \neq x$ with $a < y < b$).
Sep 22, 2015 at 6:55 comment added Alex Ravsky Yes, $e$ is the identity of the group.
Sep 22, 2015 at 6:53 comment added Salvo Tringali I don't know if there is a standard name for this, but, assuming $e$ in the OP is the identity of the group, a possibility would be "non-atomic l.o. groups" (cf. en.wikipedia.org/wiki/Atom_%28order_theory%29).
Sep 22, 2015 at 6:41 history asked Alex Ravsky CC BY-SA 3.0