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Timeline for Unbounded operator [closed]

Current License: CC BY-SA 3.0

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Sep 21, 2015 at 21:43 history closed Yemon Choi
Pietro Majer
Mikael de la Salle
Stefan Kohl
Dirk
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Sep 21, 2015 at 19:50 answer added Delio Mugnolo timeline score: 4
Sep 21, 2015 at 19:48 comment added Sergei Akbarov If $C^2$ means the space of two times continuously differentiable functions, then this operator is bounded, since it acts from $C^2[a,b]$ to $C[a,b]$, and the last space is continuously embedded into $L^2[a,b]$. Or what do you mean?
Sep 21, 2015 at 19:46 review Close votes
Sep 21, 2015 at 21:43
Sep 21, 2015 at 19:39 comment added Akai Shuichi @Chris Ramsey: To make it clearer, I have edited my question. Thanks.
Sep 21, 2015 at 19:37 history edited Akai Shuichi CC BY-SA 3.0
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Sep 21, 2015 at 19:30 comment added Chris Ramsey An illustrative example of what, why its unbounded?
Sep 21, 2015 at 19:26 review First posts
Sep 21, 2015 at 19:31
Sep 21, 2015 at 19:26 history asked Akai Shuichi CC BY-SA 3.0