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Feb 28, 2022 at 7:47 comment added Mark Grant In the non-simply connected case you can easily have infinite $0$-th and $1$-st Betti numbers, e.g. if $\pi_1(M)=\mathbb{Z}$ then $\Lambda M$ has infinitely many path components. Not sure about the higher Betti numbers.
Feb 27, 2022 at 23:15 comment added user188722 Hi Mark, can I ask a question - does this finiteness of Betti number hold only for simply connected manifolds? How about non-simply connected ones?
Sep 16, 2015 at 12:53 comment added Sinan Yalin Concerning the growth of Betti numbers of free loop spaces, it is worth mentionning also the papers of Pascal Lambrechts On the Betti numbers of the free loop space of a coformal space (JPAA 2001) and The Betti numbers of the free loop space of a connected sum ( J. London Math. Soc. 2001).
Sep 16, 2015 at 12:42 history answered Mark Grant CC BY-SA 3.0