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Sep 19, 2015 at 15:28 answer added Philip Engel timeline score: 3
Sep 19, 2015 at 15:22 comment added Philip Engel Two fibers of the projection $\mathbb{P}^1\times\mathbb{P}^1\rightarrow \mathbb{P}^1$. I will make my comment an answer, to elaborate.
Sep 17, 2015 at 15:22 answer added Lars Kastner timeline score: 2
Sep 17, 2015 at 12:29 answer added Allen Knutson timeline score: 3
Sep 16, 2015 at 14:02 comment added Pedro Montero In order to deal with toric varieties we should blow-up torus invariant points instead, no? If it is the case, you can consider the fan of $X=\operatorname{Bl}_{p_1,p_2,p_3,p_4}(\mathbb{P}^3)$ and project onto the $xy$-plane. This will give a toric morphism from $X$ onto the blow-up of $\mathbb{P}^1\times \mathbb{P}^1$ at two invariant points and then you can blow-down.
Sep 16, 2015 at 13:53 comment added user68440 I do not understand. The fibers would be curves not sufaces.
Sep 16, 2015 at 9:41 comment added Jason Starr There exists a constant morphism :) I love bad jokes.
Sep 16, 2015 at 4:27 comment added Philip Engel Maybe I'm missing something, but the inverse images of two disjoint fibers are two disjoint surfaces in the blow-up. The images of these surfaces in $\mathbb{P}^3$ must then only intersect at the four points, which is impossible, as two surfaces in $\mathbb{P}^3$ always intersect in at least a curve.
Sep 16, 2015 at 1:07 history asked user68440 CC BY-SA 3.0