Timeline for How i show this beautiful inequality :$\frac{x^n}{x^m+y^m}+\frac{y^n}{y^m+z^m}+\frac{z^n}{z^m+x^m}\geq \frac{3} {2}(\frac{1}{\sqrt{3}})^{n-m}$? [closed]
Current License: CC BY-SA 3.0
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Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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Oct 5, 2015 at 20:28 | history | edited | zeraoulia rafik | CC BY-SA 3.0 |
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Sep 16, 2015 at 22:27 | comment | added | zeraoulia rafik | @GeraldEdgar, but why this downvote to my uestion such that i hput it source ? | |
Sep 16, 2015 at 20:45 | review | Reopen votes | |||
Sep 16, 2015 at 21:14 | |||||
Sep 16, 2015 at 20:22 | history | edited | zeraoulia rafik | CC BY-SA 3.0 |
added 137 characters in body
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Sep 16, 2015 at 16:52 | history | closed |
Gerald Edgar Boris Bukh Ilya Bogdanov Nik Weaver Lucia |
Not suitable for this site | |
Sep 16, 2015 at 15:34 | comment | added | Gerald Edgar | Thank you for waiting until after the date for submitting solutions before posting here. | |
Sep 16, 2015 at 15:01 | review | Close votes | |||
Sep 16, 2015 at 16:52 | |||||
Sep 16, 2015 at 12:10 | answer | added | Peter Mueller | timeline score: 17 | |
Sep 16, 2015 at 0:01 | comment | added | Anthony Quas | Feels like a math competition inequality... | |
Sep 15, 2015 at 22:04 | comment | added | Joe Silverman | Might look a bit less messy if you let $X=\sqrt3x$, $Y=\sqrt3y$, and $Z=\sqrt3z$. That gets rid of the $(1/\sqrt3)^{n-m}$ on the right, at the cost of changing the boundary condition to $XY+YZ+ZX=3$. | |
Sep 15, 2015 at 21:10 | comment | added | GH from MO | Where did you find this inequality? | |
Sep 15, 2015 at 20:40 | history | asked | zeraoulia rafik | CC BY-SA 3.0 |