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Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Oct 5, 2015 at 20:28 history edited zeraoulia rafik CC BY-SA 3.0
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Sep 16, 2015 at 22:27 comment added zeraoulia rafik @GeraldEdgar, but why this downvote to my uestion such that i hput it source ?
Sep 16, 2015 at 20:45 review Reopen votes
Sep 16, 2015 at 21:14
Sep 16, 2015 at 20:22 history edited zeraoulia rafik CC BY-SA 3.0
added 137 characters in body
Sep 16, 2015 at 16:52 history closed Gerald Edgar
Boris Bukh
Ilya Bogdanov
Nik Weaver
Lucia
Not suitable for this site
Sep 16, 2015 at 15:34 comment added Gerald Edgar Thank you for waiting until after the date for submitting solutions before posting here.
Sep 16, 2015 at 15:01 review Close votes
Sep 16, 2015 at 16:52
Sep 16, 2015 at 12:10 answer added Peter Mueller timeline score: 17
Sep 16, 2015 at 0:01 comment added Anthony Quas Feels like a math competition inequality...
Sep 15, 2015 at 22:04 comment added Joe Silverman Might look a bit less messy if you let $X=\sqrt3x$, $Y=\sqrt3y$, and $Z=\sqrt3z$. That gets rid of the $(1/\sqrt3)^{n-m}$ on the right, at the cost of changing the boundary condition to $XY+YZ+ZX=3$.
Sep 15, 2015 at 21:10 comment added GH from MO Where did you find this inequality?
Sep 15, 2015 at 20:40 history asked zeraoulia rafik CC BY-SA 3.0