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Oct 7, 2015 at 7:08 comment added Bill Johnson True, Rauni, but the proof of the factorization theorem gives an injective $J$. Also, if you have such a factorization with a non injective $J$, you can mod out the kernel of $J$ to get a factorization through another reflexive space for which the mapping from the reflexive space is injective.
Oct 6, 2015 at 5:08 comment added Rauni Thank You for Your alternate proof. I used it in a seminar. But it seems to me that we do not use injectivity of J anywhere?
Oct 2, 2015 at 20:04 comment added Bill Johnson Yes, DFJP, Rauni.
Oct 1, 2015 at 21:46 comment added Rauni When You say "By the factorization theorem for weakly compact operators", do You refer to the DFJP Factorization or to some other result?
Sep 14, 2015 at 18:25 history answered Bill Johnson CC BY-SA 3.0