Timeline for Are compact, complex, affinely flat manifolds geodesically complete?
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Jan 29, 2020 at 21:47 | vote | accept | Mike Cocos | ||
Sep 17, 2015 at 13:57 | history | edited | Mike Cocos | CC BY-SA 3.0 |
added 19 characters in body
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Sep 16, 2015 at 7:11 | answer | added | Vladimir S Matveev | timeline score: 4 | |
Sep 15, 2015 at 1:09 | history | edited | Mike Cocos | CC BY-SA 3.0 |
added 381 characters in body
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Sep 13, 2015 at 18:15 | answer | added | Misha | timeline score: 4 | |
Sep 13, 2015 at 15:26 | comment | added | Mike Cocos | @Misha Thank you.Clearly the action does not preserve the volume so if I added that constraint(which apparently it is not necessary from the point of view of Markus conjecture) the dialation example would not work.For an affinely flat, complex surface I think I can prove that the existence of a parallel volume form implies the geodesic completeness. | |
Sep 13, 2015 at 8:05 | answer | added | Vladimir S Matveev | timeline score: 8 | |
Sep 13, 2015 at 3:20 | comment | added | Misha | Take a cyclic group of dilations of complex line fixing the origin. Now quotient the complex line minus origin by this group. | |
Sep 12, 2015 at 23:08 | comment | added | Mike Cocos | Thank you Misha. I am trying to understand your swift response. There is a 4 dimensional manifold of flat affine structures, nondiffeomorphically equivalent on the torus. Which flat affine structure are you referring to? I am obviously misreading your response. | |
S Sep 12, 2015 at 23:00 | history | suggested | Michael Albanese | CC BY-SA 3.0 |
Fixed some spelling and MathJax.
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Sep 12, 2015 at 22:54 | review | Suggested edits | |||
S Sep 12, 2015 at 23:00 | |||||
Sep 12, 2015 at 22:14 | comment | added | Misha | This is already false for complex 1-dimensional torus, where holonomy of the flat affine structure is cyclic complex affine. | |
Sep 12, 2015 at 22:07 | history | asked | Mike Cocos | CC BY-SA 3.0 |