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Jun 14, 2017 at 15:00 comment added Gorbz This is a ver very good answer. I am wondering if you could show the same for the $\mathcal{N}=4$ twist though. There things are harder since the global rotation group is $SU(2)_L \times SU(2)_R \times SU(4)_R$ which can be written as $SU(2)_L \times SU(2)_R \times SU(2)_A \times SU(2)_B \times U(1)$. Now, I do not see how exactly the spinor $(2,1,\bar{4}) \oplus (1,2,4)$ representation changes (that is how the supercharges change under the twist).
Sep 13, 2015 at 13:01 vote accept Marion
Sep 11, 2015 at 20:18 history answered D. S. Park CC BY-SA 3.0