Skip to main content
deleted 93 characters in body
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

(Retract) Retract embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be topologically embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we poseAcording to the extra condition thatcomment of Mark Grant and the imageanswer of Ryan Budney, I revise the question:

For what even $S^n$ be$n$, there is a retract embedding of theof $S^n$ in its unit tangent bundle?

(Retract) embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be topologically embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we pose the extra condition that the image of $S^n$ be a retract of the unit tangent bundle?

Retract embedding of $S^{n}$ in its unit tangent bundle

Acording to the comment of Mark Grant and the answer of Ryan Budney, I revise the question:

For what even $n$, there is a retract embedding of of $S^n$ in its unit tangent bundle?

added 15 characters in body
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

(retractRetract) embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be embeddedtopologically embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we pose the extra condition that the image of $S^n$ isbe a retract of the unit tangent bundle?

(retract) embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we pose the extra condition that the image of $S^n$ is a retract of the unit tangent bundle?

(Retract) embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be topologically embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we pose the extra condition that the image of $S^n$ be a retract of the unit tangent bundle?

Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

(retract) embedding of $S^{n}$ in its unit tangent bundle

Is there an even integer $n$ such that $S^n$ can be embedded in its unit tangent bundle $$T^{1} S^n=\{(x,y)\in S^n \times S^n \mid x.y=0\}$$ What about if we pose the extra condition that the image of $S^n$ is a retract of the unit tangent bundle?