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Sep 11, 2015 at 14:38 history edited Yusuf Mustopa CC BY-SA 3.0
minor mistake corrected
Sep 11, 2015 at 14:32 comment added Yusuf Mustopa Thanks for the correction! I will edit my answer accordingly.
Sep 11, 2015 at 7:31 comment added Remke Kloosterman There is a minor issue with your argument: If $X$ is a smooth projective surface admitting a genus 2 fibration, with a singular fiber with more than 2 irreducible components then $X$ is only birational (as $\mathbb{P}^1$-variety) to a double cover of a ruled surface. Even if you read the OP as X admits a fibration in genus two curves and there are precisely 7 singular fibers, each of them has one node (and therefore at most two irreducible components) your argument does not always work.
Sep 10, 2015 at 18:36 history answered Yusuf Mustopa CC BY-SA 3.0