Skip to main content
2 events
when toggle format what by license comment
Aug 5 at 0:45 comment added Bjorn Poonen I don't think this argument is correct. The sum here equals $\sum_{p \le n} (\log n - \log p)$, but both $\sum_{p \le n} \log n$ and $\sum_{p \le n} \log p$ are asymptotic to $n$, by the prime number theorem.
Sep 9, 2015 at 15:01 history answered Brando CC BY-SA 3.0