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Jun 10, 2010 at 16:38 comment added Cam McLeman I second that suggestion.
Apr 19, 2010 at 21:13 comment added Vladimir Dotsenko Keith, thanks! Why don't you post it as an answer here? I think it's a bit misleading that the accepted answer to this question states that every nxn traceless matrix over a PID is a commutator!
Apr 19, 2010 at 14:04 comment added KConrad Vladimir, I wrote to Zak Mesyan (who wrote a paper on trace 0 and commutators) and he told me that whether an arbitrary nxn matrix over a PID with trace 0 is a commutator is still open as far as he knows.
Apr 18, 2010 at 21:16 comment added Vladimir Dotsenko @Keith: thanks for clarifying that - looking forward to updates!
Apr 18, 2010 at 20:29 comment added KConrad I have written to someone who has worked on these kinds of problems and will post a reply when I get it.
Apr 18, 2010 at 20:22 comment added KConrad Vladimir, that is my .pdf file you linked to and I actually do not have a good citation! I may have just read the MathSciNet review as Jack did without looking at the Rosset--Rosset article itself. So I have now removed that claim from the .pdf file and will see if I can find someone to settle this question. ой....
Apr 18, 2010 at 19:41 vote accept Portland
Apr 18, 2010 at 19:41
Apr 18, 2010 at 17:29 history edited Vladimir Dotsenko CC BY-SA 2.5
added 41 characters in body
Apr 18, 2010 at 17:14 comment added Vladimir Dotsenko If it helps anyone, the proof for matrices over a field (Albert and Muckenhoupt) is available via the following link: projecteuclid.org/…
Apr 18, 2010 at 17:09 history answered Vladimir Dotsenko CC BY-SA 2.5