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Sep 19, 2015 at 11:57 comment added user91132 user1729: $\mathbb{Z}/2\mathbb{Z}$ is an abelian group with no automorphism of even order. But of course its automorphism group is not isomorphic to $\mathbb{Z}$ either. Your argument shows that $\Aut(G)$ cannot be an abelian non-trivial group with no elements of order two. So for example any non-trivial finite abelian group of odd order is ruled out.
Sep 11, 2015 at 13:32 comment added user1729 For (5), $\mathbb{Z}$ works. I think also any cyclic group of odd (prime?) order. The idea is to note that $G/Z(G)$ embeds into $\operatorname{Aut}(G)$, and hence $G$ is abelian (standard undergrad exercise). Such a group always has an automorphism of even order, assuming AOC (less standard exercise, not sure of level), a contradiction.
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Sep 10, 2015 at 13:48
Sep 5, 2015 at 10:08 comment added Ali Taghavi @JasonStarr Thank you for your comment. As you can guess the "s" character in my keyboard had some problem and I was not aware of that. Any way, is there an obtruction to have compact Haudorff space X with Homeo(X) isomorphic to G?
Sep 4, 2015 at 23:26 comment added Jason Starr @AliTaghavi: "could you pleae more explain on thi topology?" I would like to recommend that you use the spell checker that is built into the MO comments system. A subset $U$ of $X$ is open with respect to the topology I mention if and only if it satisfies all of the following conditions: for every $(g,h)$ in $G\times G$, (a) if $U$ contains $t_g$ then $U$ contains $u_{g,h}$, (b) if $U$ contains $t_h$ or $u_{g,h}$, then $U$ contains $v_{g,h}$, and (c) if $U$ contains $t_{g\cdot h}$ or $v_{g,h}$ then $U$ contains $w_{g,h}$.
Sep 4, 2015 at 21:34 history edited Ali Taghavi
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Sep 4, 2015 at 21:00 comment added Ali Taghavi @JasonStarr could you pleae more explain on thi topology?any reference?I there obstruction to find a compact hausdorff space?
Sep 4, 2015 at 20:57 comment added Ali Taghavi @YiftachBarnea thank you for your comment. i revise the question.
Sep 4, 2015 at 20:56 history edited Ali Taghavi CC BY-SA 3.0
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Sep 4, 2015 at 19:08 comment added Yiftach Barnea Do you mean any structure or a structure?
Sep 4, 2015 at 18:57 comment added Jason Starr Every group $G$ is the group of homeomorphisms of a topological space $X$. Let $X$ have as point set $\{t_g | g\in G\} \sqcup \{u_{g,h},v_{g,h}, w_{g,h} | (g,h) \in G\times G\}$. Define the topology to be the finest topology satisfying the following specialization conditions: for every $(g,h)\in G\times G$, impose $u_{g,h}$ specializes to $t_g$, $v_{g,h}$ specializes to $u_{g,h}$, $t_g$ and $t_h$, and $w_{g,h}$ specializes to $v_{g,h}$, $u_{g,h}$, $t_g$, $t_h$ and $t_{g\cdot h}$.
Sep 4, 2015 at 18:26 history edited Arturo Magidin CC BY-SA 3.0
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Sep 4, 2015 at 17:32 history edited Minimus Heximus CC BY-SA 3.0
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Sep 4, 2015 at 17:06 history made wiki Post Made Community Wiki by Todd Trimble
Sep 4, 2015 at 17:05 history edited Ali Taghavi CC BY-SA 3.0
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Sep 4, 2015 at 16:57 history edited Ali Taghavi CC BY-SA 3.0
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Sep 4, 2015 at 16:49 history asked Ali Taghavi CC BY-SA 3.0