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Sep 5, 2015 at 12:47 comment added user43326 No, in homology there are not only the elements $Q^I(\iota _n)$'s but their products. And they are not primitive.
Sep 5, 2015 at 12:44 comment added QSR Dear Prof., you mentioned that "since the fundamental class is primitive, so all the classes obtained by Dyer-Lashof operations are primitive as well". But if this is true for the homology, the cup product of cohomology would be trivial.
Sep 3, 2015 at 14:47 comment added user43326 The first fact is the consequence of the fact that $\Omega ^{\infty}$ is a right adjoint, the second, as is explained, follows from the fact that all polynomial generators of $H_*(QS^n)$ with $n>0$ are primitive. I presume you can find all of these (except the first one ) in somewhere section 3 of Wellington's book, but unfortunately I don't have it on the hand.
Sep 3, 2015 at 14:36 history edited user43326 CC BY-SA 3.0
Added a detailed proof.
Sep 3, 2015 at 12:47 comment added QSR Thanks, Prof. Could you explain more? Which page could I find the results?
Sep 3, 2015 at 12:34 vote accept QSR
Sep 3, 2015 at 12:43
Sep 3, 2015 at 12:28 history answered user43326 CC BY-SA 3.0