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Jul 8, 2019 at 16:52 comment added Taras Banakh @AlexRavsky Yes, you are right. $B$ should be a subset of $C$.
Jul 8, 2019 at 16:51 history edited Taras Banakh CC BY-SA 4.0
edited body
Jul 3, 2019 at 1:13 comment added Alex Ravsky I guess you mean the 3-element subset $B$ of $C$, not of $S$.
Sep 1, 2015 at 15:39 history edited Taras Banakh CC BY-SA 3.0
There was a gap in the previous proof. So, an alternative proof is presented.
Sep 1, 2015 at 15:07 history edited Taras Banakh CC BY-SA 3.0
fixed a misprint
Sep 1, 2015 at 12:06 history answered Taras Banakh CC BY-SA 3.0