Timeline for A quadrant of residues
Current License: CC BY-SA 3.0
34 events
when toggle format | what | by | license | comment | |
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Jul 22, 2017 at 21:41 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jun 22, 2017 at 20:56 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 23, 2017 at 20:56 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Apr 23, 2017 at 20:38 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Mar 24, 2017 at 22:54 | comment | added | LSpice | Does the tag indicate that this subject is to be studied by @TheoJohnson-Freyd? | |
Mar 24, 2017 at 20:19 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Feb 22, 2017 at 20:13 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jan 23, 2017 at 16:12 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Dec 24, 2016 at 15:44 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Nov 24, 2016 at 15:38 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Oct 25, 2016 at 14:50 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Sep 25, 2016 at 14:18 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Aug 26, 2016 at 13:34 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jul 27, 2016 at 13:13 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jun 27, 2016 at 12:31 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 28, 2016 at 12:09 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Oct 1, 2015 at 7:53 | history | undeleted | user76479 | ||
Oct 1, 2015 at 7:53 | history | deleted | user76479 | via Vote | |
Sep 1, 2015 at 6:07 | answer | added | joro | timeline score: -1 | |
Aug 31, 2015 at 7:15 | comment | added | joro | Hm, I noticed mistake in my current approach. | |
Aug 31, 2015 at 6:14 | comment | added | user76479 | @joro could you give the procedure? | |
Aug 31, 2015 at 5:10 | comment | added | joro | I think you can solve in $O( (AB)^2)$ or similar distinct square of two distinct. | |
Aug 31, 2015 at 0:49 | comment | added | user76479 | What is frustrating is guessing any pairs is still insufficient. | |
Aug 31, 2015 at 0:46 | history | undeleted | user76479 | ||
Aug 31, 2015 at 0:44 | history | deleted | user76479 | via Vote | |
Aug 31, 2015 at 0:39 | comment | added | user76479 | This is a method I tried for this problem and am not successful so far mathoverflow.net/questions/215999/… | |
Aug 31, 2015 at 0:37 | history | edited | user76479 | CC BY-SA 3.0 |
added 4 characters in body
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Aug 31, 2015 at 0:37 | comment | added | user76479 | Ok I will change. | |
Aug 31, 2015 at 0:36 | comment | added | Anthony Quas | So that would seem to be a much tidier formulation. | |
Aug 31, 2015 at 0:36 | comment | added | user76479 | I could have used $(ABCD)^2$ instead of $wxyz$. | |
Aug 31, 2015 at 0:34 | comment | added | user76479 | I am assuming here $w,x,y,z$ are equal sizes which seems to be hardest case. For unequal cases, it seems plausible we can get $\beta=3$ so I am thinking may be $\beta=4$ is case to be seen. | |
Aug 31, 2015 at 0:33 | review | Close votes | |||
Aug 31, 2015 at 12:36 | |||||
Aug 31, 2015 at 0:32 | comment | added | Anthony Quas | I don't see what's wrong with this question either - just upvoted. Isn't it a bit strange to express the number of steps in terms of the unknowns? Is there a particular reason that you interested in the threshold $(wxyz)^{\frac 14-\epsilon}$ rather than something else? | |
Aug 31, 2015 at 0:14 | history | asked | user76479 | CC BY-SA 3.0 |