Timeline for Does an element in the center of universal enveloping algebra becomes a scalar in irreducible representations?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 31, 2015 at 16:19 | vote | accept | Junekey Jeon | ||
| Aug 31, 2015 at 9:03 | comment | added | S. Carnahan♦ | @JunekeyJeon Yes, if $G$ is connected, then $G$ is generated by exponentials of elements in the Lie algebra. This implies the two versions of invariance are the same. | |
| Aug 30, 2015 at 2:26 | comment | added | Junekey Jeon | Wow, nice and simple counterexample! Thank you. So, what if G is connected? Is ad-invariance implies Ad-invariance for that case? | |
| Aug 29, 2015 at 20:17 | history | answered | S. Carnahan♦ | CC BY-SA 3.0 |