Timeline for symmetric measurable 2-cocycles on compact abelian groups vanish?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 30, 2015 at 9:59 | vote | accept | Jiang | ||
| Aug 29, 2015 at 2:46 | comment | added | Amritanshu Prasad | That seems to do the job for second countable compact abelian groups. Thanks for digging it out. | |
| Aug 28, 2015 at 20:16 | comment | added | Jiang | thanks, it seems that theorem 10 in ams.org/mathscinet-getitem?mr=414775 is the statement you are talking above? | |
| Aug 28, 2015 at 3:16 | comment | added | Amritanshu Prasad | Indeed my answer leaves that issue unaddressed. Isn't there a theorem that says that every measurable cocycle is cohomologous to a continuous one? I can't remember where I have seen such statements. | |
| Aug 27, 2015 at 13:40 | comment | added | Jiang | thanks, but I am still worried that the 2-cocycle relation holds almost everywhere, not everywhere in my problem, is it appropriate to have a pure algebraic argument as above to show this? | |
| Aug 27, 2015 at 13:14 | history | edited | Amritanshu Prasad | CC BY-SA 3.0 |
added 14 characters in body
|
| Aug 27, 2015 at 13:01 | history | answered | Amritanshu Prasad | CC BY-SA 3.0 |