Skip to main content
6 events
when toggle format what by license comment
Aug 26, 2015 at 16:48 comment added Josh Brown Kramer @kodlu, the support of $A - B$ is $B \setminus A$, which is a subset of $B$. Maybe it's not right to say it supported on $B$, but at any rate, the fact that $\mathcal{C}$ is 2-Sperner still holds.
Aug 26, 2015 at 16:47 comment added Josh Brown Kramer @NoamD.Elkies, I read the problem too hastily. I kept interpreting $2^{n/2}$ as $2^{n - 1}$. With that in mind, my answer is clearly unhelpful.
Aug 26, 2015 at 5:25 comment added kodlu Noam D. Elkies' comment is correct. Also, the statement $A-B$ is supported on $B$ in the answer is incorrect.
Aug 26, 2015 at 4:35 comment added Noam D. Elkies The growth of the largest binomial coefficient(s) $n \choose m$ is $\sim 2^n / \sqrt{n}$. How do you get "much smaller than $2^{n/2}$"?
Aug 26, 2015 at 2:11 review Late answers
Aug 26, 2015 at 6:11
Aug 26, 2015 at 1:54 history answered Josh Brown Kramer CC BY-SA 3.0