Timeline for 2-dimensional sublattices with all vectors having very big square (in absolute value)
Current License: CC BY-SA 3.0
21 events
when toggle format | what | by | license | comment | |
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Nov 4, 2015 at 14:42 | vote | accept | Misha Verbitsky | ||
S Sep 9, 2015 at 1:47 | history | bounty ended | David E Speyer | ||
S Sep 9, 2015 at 1:47 | history | notice removed | David E Speyer | ||
Sep 9, 2015 at 0:41 | answer | added | Noam D. Elkies | timeline score: 3 | |
Sep 1, 2015 at 22:33 | answer | added | Misha Verbitsky | timeline score: 1 | |
S Sep 1, 2015 at 15:41 | history | suggested | GNiklasch | CC BY-SA 3.0 |
qualifier nonzero needed in one place
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Sep 1, 2015 at 15:23 | review | Suggested edits | |||
S Sep 1, 2015 at 15:41 | |||||
Sep 1, 2015 at 14:32 | history | edited | David E Speyer | CC BY-SA 3.0 |
deleted 35 characters in body
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Sep 1, 2015 at 13:33 | comment | added | Fedor Petrov | Maybe, we may remove small values of (x,x) using Chinese remainder theorem? | |
S Sep 1, 2015 at 12:53 | history | bounty started | David E Speyer | ||
S Sep 1, 2015 at 12:53 | history | notice added | David E Speyer | Draw attention | |
Sep 1, 2015 at 12:52 | history | edited | David E Speyer | CC BY-SA 3.0 |
added 1297 characters in body
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Aug 28, 2015 at 0:22 | answer | added | few_reps | timeline score: 3 | |
Aug 26, 2015 at 10:59 | history | edited | Misha Verbitsky | CC BY-SA 3.0 |
added 10 characters in body
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Aug 26, 2015 at 10:59 | comment | added | Misha Verbitsky | definitely! thanks for pointing this out, I amended the question | |
Aug 25, 2015 at 22:48 | comment | added | Anthony Quas | Presumably you want your lattice not to be a multiple of any other lattice? | |
Aug 25, 2015 at 22:16 | comment | added | Will Jagy | Oh, that probably does demand some kind of diophantine approximation argument, then; I don't quite recall what you commented earlier on the proof you found not really to your liking. | |
Aug 25, 2015 at 21:38 | history | edited | Misha Verbitsky | CC BY-SA 3.0 |
added 11 characters in body
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Aug 25, 2015 at 21:38 | comment | added | Misha Verbitsky | Sorry! I misstated the question: I should add an assumption that this 2-dimensional lattice is not definite! | |
Aug 25, 2015 at 20:48 | comment | added | Will Jagy | seems to me there is a sublattice of dimension $\lceil \frac{n}{2} \rceil$ on which your nondegenerate form is definite. Does that suffice? | |
Aug 25, 2015 at 19:56 | history | asked | Misha Verbitsky | CC BY-SA 3.0 |