Timeline for Why does $d^n \exp(-x-x^{-1})/(dx)^n$ only have $n$ positive real zeroes?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Dec 3, 2015 at 8:36 | comment | added | Johannes Trost | +1 fro the explanation and also for the figures. | |
| Aug 26, 2015 at 10:40 | comment | added | Peter Mueller | The discriminant of $\phi_n(x,\alpha)$, with respect to $x$, seems to be a polynomial in $\alpha$ with all coefficients of the same sign (or $0$). If one can prove that, this would be the missing piece. | |
| Aug 26, 2015 at 9:20 | history | edited | Peter Mueller | CC BY-SA 3.0 |
another fix
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| Aug 26, 2015 at 8:51 | history | edited | Peter Mueller | CC BY-SA 3.0 |
simplified the partial proof, fixed small errors
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| Aug 25, 2015 at 19:19 | history | edited | Peter Mueller | CC BY-SA 3.0 |
added images which illustrate the argument
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| Aug 25, 2015 at 19:14 | history | edited | Peter Mueller | CC BY-SA 3.0 |
added images which illustrate the argument
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| Aug 25, 2015 at 15:22 | history | edited | Peter Mueller | CC BY-SA 3.0 |
added 585 characters in body
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| Aug 25, 2015 at 11:46 | history | answered | Peter Mueller | CC BY-SA 3.0 |