Timeline for On the Riesz representation theorem
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Aug 25, 2015 at 9:14 | comment | added | Arnold Neumaier | @QiaochuYuan: I see. Although asking for more seems interesting, the pointwise construction is enough for me. | |
| Aug 24, 2015 at 22:56 | comment | added | Qiaochu Yuan | I think Eric is asking whether you wanted some kind of uniformity with respect to $\psi$ in that limit. (It can be interpreted as a limit of functions of $\psi$ rather than just a limit of numbers.) | |
| Aug 24, 2015 at 17:23 | vote | accept | Arnold Neumaier | ||
| Aug 24, 2015 at 16:33 | answer | added | Eric Wofsey | timeline score: 9 | |
| Aug 24, 2015 at 16:09 | history | edited | Arnold Neumaier | CC BY-SA 3.0 |
deleted 9 characters in body
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| Aug 24, 2015 at 16:08 | comment | added | Arnold Neumaier | @EricWofsey: The limit is a limit of numbers, hence there is no weaker or stronger version. How to construct the net? | |
| Aug 24, 2015 at 15:18 | comment | added | Eric Wofsey | Do you want that limit to just hold pointwise, or do you want something stronger? If you just want it pointwise, the Riesz representation theorem has nothing to do with this--you can find such a net for any $\Phi$ (because you can find a $\phi$ that works for any finite set of $\psi$s). On the other hand, if you restrict to sequences, $\Phi$ does have to be bounded if $V$ is complete, but this is not obvious (it follows from the Banach-Steinhaus theorem). | |
| Aug 24, 2015 at 15:07 | history | edited | Arnold Neumaier | CC BY-SA 3.0 |
improved choice of variables
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| Aug 24, 2015 at 14:58 | history | asked | Arnold Neumaier | CC BY-SA 3.0 |