Timeline for Examples of Banach spaces and their duals
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 9, 2011 at 1:42 | vote | accept | Tom LaGatta | ||
| Aug 8, 2011 at 21:24 | answer | added | dan232 | timeline score: 1 | |
| Apr 16, 2010 at 16:23 | vote | accept | Tom LaGatta | ||
| Aug 9, 2011 at 1:42 | |||||
| Apr 16, 2010 at 16:01 | history | edited | Tom LaGatta | CC BY-SA 2.5 |
added 4 characters in body
|
| Apr 16, 2010 at 12:28 | comment | added | Gerald Edgar | Note ... you mean Radon measures on [0,1], not on X . | |
| Apr 16, 2010 at 12:27 | answer | added | Gerald Edgar | timeline score: 4 | |
| Apr 16, 2010 at 2:36 | comment | added | Yemon Choi | Just to add to Harald's comment: of course this doesn't determine the dual space up to isometry, but up to (linear, bicontinuous) isomorphism. In many contexts one only cares about the Banach space up to isomorphism, but occasionally one might wish to determine the norm more precisely. | |
| Apr 16, 2010 at 2:30 | comment | added | Harald Hanche-Olsen |
The $\operatorname{Sym}$ is a red herring here. Since $X=C^{2+\alpha}(U)\otimes\operatorname{Sym}$, you get $X^*=C^{2+\alpha}(U)^*\otimes\operatorname{Sym}^*$. The same goes if $\operatorname{Sym}$ is replaced by any finite-dimensional space. (The tensor product of two infinite dimensional Banach space is an entirely different kettle of fish, of course.)
|
|
| Apr 16, 2010 at 1:51 | answer | added | Deane Yang | timeline score: 3 | |
| Apr 16, 2010 at 1:29 | history | asked | Tom LaGatta | CC BY-SA 2.5 |