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Aug 21, 2015 at 3:07 comment added user2700 @DavidWhite, even though $X$ and $Y$ can be equipped with the structure of a simplical complex, by which I mean they admit homeomorphisms with the geometric realization of some abstract simplicial complex, the maps $X \rightrightarrows Y$ are not necessarily maps of simplicial complexes a priori (i.e. they need not come from maps of abstract simplicial complexes). If you could find triangulations of X and Y such that both maps are simplicial, then the coeq as topological spaces would agree with the geometric realization of the coeq in the category of abstract simplicial complexes.
Aug 20, 2015 at 16:34 comment added Benjamin Steinberg I suspect the op wants to have the colimit agree with the one in top spaces.
Aug 20, 2015 at 13:01 comment added David White Doesn't the category of simplicial complexes have all small limits and colimits? Does this help? A reference is math.stackexchange.com/questions/492072/…
Aug 19, 2015 at 17:29 review First posts
Aug 19, 2015 at 17:45
Aug 19, 2015 at 17:25 history asked user2700 CC BY-SA 3.0