Timeline for What is the type of the surfaces $x^5 - y^5 + z^2 + x=0$ and $x^5 - y^5 + z^2 + x+1=0$?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 20, 2015 at 6:53 | vote | accept | joro | ||
| Aug 19, 2015 at 13:47 | comment | added | Alex Degtyarev | Of course, I presume that you compactify your surface and resolve the singularities. Since, in your case, the affine part chosen seems nonsingular, the compactification can also be chosen nonsingular. | |
| Aug 19, 2015 at 13:45 | comment | added | Alex Degtyarev | Yes, it is. Once again, the double plane ramified at a sextic is a $K3$ iff all singular points of the sextic, if any, are simple (= $ADE$ = $0$-modal =?= rational double points + 12 more definitions/names). $A_1$ is the simplest simple singularity :) | |
| Aug 19, 2015 at 13:25 | comment | added | joro | Isn't $(0:1:1)$ double singularity on your first curve? | |
| Aug 19, 2015 at 9:43 | history | answered | Alex Degtyarev | CC BY-SA 3.0 |