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Aug 25, 2015 at 17:40 answer added grok timeline score: 0
Aug 22, 2015 at 11:08 comment added Edgar Ndie yes I did. In that article, Brunner & Sidki want to prove that $GL_n(\mathbb{Z})$ is an automaton group. But I think it's not the case. Anyway I don't see any link with the fact that $BS(n,n)$ is an automaton group, $F_{|n|}\rtimes\mathbb{Z},$ and the fact $GL_n(\mathbb{Z})$ is an automaton group. The only link (which is false) I see is even if $BS(n,n)$ is a subgroup of $GL_n(\mathbb{Z})$ and $GL_n(\mathbb{Z})$ is an automaton group, it does not make $BS(n,n)$ an automaton group.
Aug 22, 2015 at 8:15 comment added Derek Holt Presumably you have looked at the article by Brunner & Sidki?
Aug 22, 2015 at 6:01 comment added Edgar Ndie In fact I meant both statements. sorry for the confusion
Aug 19, 2015 at 15:44 comment added Derek Holt It is not at all clear what you mean by "this statement". Which statement?
Aug 19, 2015 at 10:08 answer added YCor timeline score: 3
Aug 19, 2015 at 9:12 history asked Edgar Ndie CC BY-SA 3.0